Monday, December 6, 2010

Module 4_ Tensile Test

Dear Students

refer to the link and to tensile stress-strain curve below to answer the following questions:
http://www.esm.psu.edu/courses/emch13d/design/animation/Fnecking.html

1. Define the following terms:

  • the ultimate tensile force,

  • fracture force,

  • elastic range

  • plastic range

2. Explain how to get the yield point from the graph.


8 comments:

  1. 1. It is the maximum resistance to fracture. It is equivalent to the maximum load that can be carried by one square inch of cross-sectional area when the load is applied as simple tension. It is expressed in pounds per square inch.

    ReplyDelete
  2. In materials science, the strength of a material is its ability to withstand an applied stress without failure. The applied stress may be tensile, compressive, or shear. It is a subject which deals with loads, elastic and forces acting on the material. For example, an external load applied to an elastic material or internal forces acting on the material. Deformation (e.g. bending) of the material is called strain, while the intensity of the internal resisting force is called stress. The strength of any material relies on three different type of analytical method: strength, stiffness and stability, where strength means load carrying capacity, stiffness means deformation or elongation, and stability means ability to maintain its initial configuration. Yield strength refers to the point on the engineering stress-strain curve (as opposed to true stress-strain curve) beyond which the material begins deformation that cannot be reversed upon removal of the loading. Ultimate strength refers to the point on the engineering stress-strain curve corresponding to the maximum stress.

    ReplyDelete
  3. 1. It is the maximum resistance to fracture. It is equivalent to the maximum load that can be carried by one square inch of cross-sectional area when the load is applied as simple tension. It is expressed in pounds per square inch

    abdulla khalfan

    11-06

    ReplyDelete
  4. 1. It is the maximum resistance to fracture. It is equivalent to the

    maximum load that can be carried by one square inch of cross-sectional

    area when the load is applied as simple tension. It is expressed in pounds

    per square inch

    ReplyDelete
  5. 1. It is the maximum resistance to fracture. It is equivalent to the
    maximum load that can be carried by one square inch of cross-sectional

    area when the load is applied as simple tension. It is expressed in pounds

    per square inch


    abdulla mohammed almuhiri

    11-06

    90008

    ReplyDelete
  6. 1. It is the maximum resistance to fracture. It is equivalent to the maximum load that can be carried by one square inch of cross-sectional area when the load is applied as simple tension. It is expressed in pounds per square inch



    hussain zaid alafifi

    11-06

    90011

    ReplyDelete
  7. @ It is the maximum resistance to fracture. It is equivalent to the maximum load that can be carried by one square inch of cross-sectional area when the load is applied as simple tension. It is expressed in pounds per square inch

    abdullah rabei ali
    11-6
    90014

    ReplyDelete
  8. 1. It is the maximum resistance to fracture. It is equivalent to the maximum load that can be carried by one square inch of cross-sectional area when the load is applied as simple tension. It is expressed in pounds per square inch.

    hamdan obaid

    11-6

    ReplyDelete